c^2-3c=10

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Solution for c^2-3c=10 equation:


Simplifying
c2 + -3c = 10

Reorder the terms:
-3c + c2 = 10

Solving
-3c + c2 = 10

Solving for variable 'c'.

Reorder the terms:
-10 + -3c + c2 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + -3c + c2 = 0

Factor a trinomial.
(-2 + -1c)(5 + -1c) = 0

Subproblem 1

Set the factor '(-2 + -1c)' equal to zero and attempt to solve: Simplifying -2 + -1c = 0 Solving -2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1c = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1c = 0 + 2 -1c = 0 + 2 Combine like terms: 0 + 2 = 2 -1c = 2 Divide each side by '-1'. c = -2 Simplifying c = -2

Subproblem 2

Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5

Solution

c = {-2, 5}

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